2548 Destroy Sequential Targets
2548 Destroy Sequential Targets
Destroy Sequential Targets 
You are given a 0-indexed array nums consisting of positive integers, representing targets on a number line. You are also given an integer space.
You have a machine which can destroy targets. Seeding the machine with some nums[i] allows it to destroy all targets with values that can be represented as nums[i] + c * space, where c is any non-negative integer. You want to destroy the maximum number of targets in nums.
Return* the minimum value of nums[i] you can seed the machine with to destroy the maximum number of targets.*
Example 1:
1
2
3
4
5
6
7
**Input:** nums = [3,7,8,1,1,5], space = 2
**Output:** 1
**Explanation:** If we seed the machine with nums[3], then we destroy all targets equal to 1,3,5,7,9,...
In this case, we would destroy 5 total targets (all except for nums[2]).
It is impossible to destroy more than 5 targets, so we return nums[3].
Example 2:
1
2
3
4
5
6
7
**Input:** nums = [1,3,5,2,4,6], space = 2
**Output:** 1
**Explanation:** Seeding the machine with nums[0], or nums[3] destroys 3 targets.
It is not possible to destroy more than 3 targets.
Since nums[0] is the minimal integer that can destroy 3 targets, we return 1.
Example 3:
1
2
3
4
5
**Input:** nums = [6,2,5], space = 100
**Output:** 2
**Explanation:** Whatever initial seed we select, we can only destroy 1 target. The minimal seed is nums[1].
Constraints:
1
2
3
1 <= nums.length <= 105
1 <= nums[i] <= 109
1 <= space <= 109
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
class Solution:
def destroyTargets(self, nums: List[int], space: int) -> int:
remainder_count = {}
# Dictionary to store minimum number for each remainder
min_number = {}
# Group numbers by remainder and track minimum in each group
for num in nums:
r = num % space
remainder_count[r] = remainder_count.get(r, 0) + 1
min_number[r] = min(min_number.get(r, float('inf')), num)
max_targets = max(remainder_count.values())
min_seed = float('inf')
# Find minimum seed that can destroy maximum targets
for r in remainder_count:
if remainder_count[r] == max_targets:
min_seed = min(min_seed, min_number[r])
return min_seed
This post is licensed under CC BY 4.0 by the author.