73 Set Matrix Zeroes
73 Set Matrix Zeroes
Set Matrix Zeroes 
Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0’s.
You must do it in place.
Example 1:
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**Input:** matrix = [[1,1,1],[1,0,1],[1,1,1]]
**Output:** [[1,0,1],[0,0,0],[1,0,1]]
Example 2:
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**Input:** matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
**Output:** [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
Constraints:
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m == matrix.length
n == matrix[0].length
1 <= m, n <= 200
-231 <= matrix[i][j] <= 231 - 1
Follow up:
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A straightforward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
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class Solution:
def setZeroes(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
def changer(i , j , matrix, t):
if i >= len(matrix) or j >= len(matrix[0]) or i < 0 or j < 0 :
return
if matrix[i][j] != 0:
matrix[i][j] = t
changer(i - 1, j , matrix, t)
def changef(i , j , matrix, t):
if i >= len(matrix) or j >= len(matrix[0]) or i < 0 or j < 0 :
return
if matrix[i][j] != 0:
matrix[i][j] = t
changef(i + 1, j , matrix, t)
def changecolr(i, j , matrix, t):
if i >= len(matrix) or j >= len(matrix[0]) or i < 0 or j < 0 :
return
if matrix[i][j] != 0:
matrix[i][j] = t
changecolr(i , j - 1 , matrix, t)
def changecolf(i, j , matrix, t):
if i >= len(matrix) or j >= len(matrix[0]) or i < 0 or j < 0 :
return
if matrix[i][j] != 0:
matrix[i][j] = t
changecolf(i , j + 1 , matrix, t)
for i, k in enumerate(matrix):
for j, l in enumerate(matrix[i]):
if l == 0:
changer(i , j , matrix, "s")
changef(i , j , matrix, "s")
changecolr(i , j , matrix, "s")
changecolf(i , j , matrix, "s")
for i, k in enumerate(matrix):
for j, l in enumerate(matrix[i]):
if l == "s":
matrix[i][j] = 0
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