Post

624 Maximum Distance In Arrays

624 Maximum Distance In Arrays

Maximum Distance in Arrays imagenull

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class Solution:
    def maxDistance(self, arrays: List[List[int]]) -> int:
        start_elem = []
        end_elem = []
        

        for i,k in enumerate(arrays):
            heapq.heappush(start_elem, (k[0],i))

        for i,k in enumerate(arrays):
            heapq.heappush(end_elem, (-1 * k[len(k)-1],i) ) 
        diff = 0
        min_elem = 0
        max_elem = 0
        is_first = True
        while (len(start_elem) > 0):
            a = heapq.heappop(start_elem)
            b = heapq.heappop(end_elem)
            #print(a,b)
            if a[1] != b[1] and is_first:
                return abs(a[0] + b[0])
            else: 
                if is_first:
                    min_elem = a[0]
                    max_elem = b[0]
                    is_first = False
                else:
                    return max(abs(min_elem + b[0]), abs(max_elem + a[0] ))

        return 0
            
        



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