48 Rotate Image
48 Rotate Image
Rotate Image 
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
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**Input:** matrix = [[1,2,3],[4,5,6],[7,8,9]]
**Output:** [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
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**Input:** matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
**Output:** [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Constraints:
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n == matrix.length == matrix[i].length
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000
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impl Solution {
pub fn rotate(matrix: &mut Vec<Vec<i32>>) {
let l = matrix.len() - 1;
if l == 0 {
return;
}
fn recurse(i: usize, j: usize, matrix: &mut Vec<Vec<i32>>, val: i32) {
if matrix[i][j] > 1000 || matrix[i][j] < -1000 {
return;
}
let old = matrix[i][j];
matrix[i][j] = val * 2001;
let l = matrix.len() - 1;
recurse(j, l - i, matrix, old);
}
for i in 0..matrix.len() {
for j in 0..matrix.len() {
if matrix[i][j] <= 1000 && matrix[i][j] >= -1000 {
recurse(j, l - i, matrix, matrix[i][j]);
}
}
}
for i in 0..matrix.len() {
for j in 0..matrix.len() {
matrix[i][j] = matrix[i][j] / 2001;
}
}
}
}
This post is licensed under CC BY 4.0 by the author.

