Post

3790 Fruits Into Baskets Ii

3790 Fruits Into Baskets Ii

Fruits Into Baskets II image

You are given two arrays of integers, fruits and baskets, each of length n, where fruits[i] represents the quantity of the ith type of fruit, and baskets[j] represents the capacity of the jth basket.

From left to right, place the fruits according to these rules:

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Each fruit type must be placed in the **leftmost available basket** with a capacity **greater than or equal** to the quantity of that fruit type.
Each basket can hold **only one** type of fruit.
If a fruit type **cannot be placed** in any basket, it remains **unplaced**.

Return the number of fruit types that remain unplaced after all possible allocations are made.

 

Example 1:

Input: fruits = [4,2,5], baskets = [3,5,4]

Output: 1

Explanation:

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fruits[0] = 4 is placed in baskets[1] = 5.
fruits[1] = 2 is placed in baskets[0] = 3.
fruits[2] = 5 cannot be placed in baskets[2] = 4.

Since one fruit type remains unplaced, we return 1.

Example 2:

Input: fruits = [3,6,1], baskets = [6,4,7]

Output: 0

Explanation:

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fruits[0] = 3 is placed in baskets[0] = 6.
fruits[1] = 6 cannot be placed in baskets[1] = 4 (insufficient capacity) but can be placed in the next available basket, baskets[2] = 7.
fruits[2] = 1 is placed in baskets[1] = 4.

Since all fruits are successfully placed, we return 0.

 

Constraints:

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n == fruits.length == baskets.length
1 <= n <= 100
1 <= fruits[i], baskets[i] <= 1000
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impl Solution {
    pub fn num_of_unplaced_fruits(fruits: Vec<i32>, baskets: Vec<i32>) -> i32 {
        // START BY PLACING THE largest fruit 
        // if largest fruit is placed in a so can all other fruits be placed
        // no it says leftmost basket
        // in that case simply assign to each basket
        // one way is 2 for loop
        // what if we keep a track of largest basket to the left
        let mut result = 0;
        let mut baskets_mut = baskets.clone();
        for k in fruits {
            let mut found = false;
            for l in baskets_mut.iter_mut() {
                if k <= *l {
                    *l = 0;
                    found = true;
                    break;
                }
            }
            if ! found {
                result += 1;
            }
        }
        return result;


    }
}



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