2023 Design Movie Rental System

Design Movie Rental System

You have a movie renting company consisting of n shops. You want to implement a renting system that supports searching for, booking, and returning movies. The system should also support generating a report of the currently rented movies.

Each movie is given as a 2D integer array entries where entries[i] = [shopi, moviei, pricei] indicates that there is a copy of movie moviei at shop shopi with a rental price of pricei. Each shop carries at most one copy of a movie moviei.

The system should support the following functions:

**Search**: Finds the **cheapest 5 shops** that have an **unrented copy** of a given movie. The shops should be sorted by **price** in ascending order, and in case of a tie, the one with the **smaller **shopi should appear first. If there are less than 5 matching shops, then all of them should be returned. If no shop has an unrented copy, then an empty list should be returned.
**Rent**: Rents an **unrented copy** of a given movie from a given shop.
**Drop**: Drops off a **previously rented copy** of a given movie at a given shop.
**Report**: Returns the **cheapest 5 rented movies** (possibly of the same movie ID) as a 2D list res where res[j] = [shopj, moviej] describes that the jth cheapest rented movie moviej was rented from the shop shopj. The movies in res should be sorted by **price **in ascending order, and in case of a tie, the one with the **smaller **shopj should appear first, and if there is still tie, the one with the **smaller **moviej should appear first. If there are fewer than 5 rented movies, then all of them should be returned. If no movies are currently being rented, then an empty list should be returned.

Implement the MovieRentingSystem class:

MovieRentingSystem(int n, int[][] entries) Initializes the MovieRentingSystem object with n shops and the movies in entries.
List<Integer> search(int movie) Returns a list of shops that have an **unrented copy** of the given movie as described above.
void rent(int shop, int movie) Rents the given movie from the given shop.
void drop(int shop, int movie) Drops off a previously rented movie at the given shop.
List<List<Integer>> report() Returns a list of cheapest **rented** movies as described above.

Note: The test cases will be generated such that rent will only be called if the shop has an unrented copy of the movie, and drop will only be called if the shop had previously rented out the movie.

 

Example 1:

**Input**
["MovieRentingSystem", "search", "rent", "rent", "report", "drop", "search"]
[[3, [[0, 1, 5], [0, 2, 6], [0, 3, 7], [1, 1, 4], [1, 2, 7], [2, 1, 5]]], [1], [0, 1], [1, 2], [], [1, 2], [2]]
**Output**
[null, [1, 0, 2], null, null, [[0, 1], [1, 2]], null, [0, 1]]

**Explanation**
MovieRentingSystem movieRentingSystem = new MovieRentingSystem(3, [[0, 1, 5], [0, 2, 6], [0, 3, 7], [1, 1, 4], [1, 2, 7], [2, 1, 5]]);
movieRentingSystem.search(1);  // return [1, 0, 2], Movies of ID 1 are unrented at shops 1, 0, and 2. Shop 1 is cheapest; shop 0 and 2 are the same price, so order by shop number.
movieRentingSystem.rent(0, 1); // Rent movie 1 from shop 0. Unrented movies at shop 0 are now [2,3].
movieRentingSystem.rent(1, 2); // Rent movie 2 from shop 1. Unrented movies at shop 1 are now [1].
movieRentingSystem.report();   // return [[0, 1], [1, 2]]. Movie 1 from shop 0 is cheapest, followed by movie 2 from shop 1.
movieRentingSystem.drop(1, 2); // Drop off movie 2 at shop 1. Unrented movies at shop 1 are now [1,2].
movieRentingSystem.search(2);  // return [0, 1]. Movies of ID 2 are unrented at shops 0 and 1. Shop 0 is cheapest, followed by shop 1.

 

Constraints:

1 <= n <= 3 * 105
1 <= entries.length <= 105
0 <= shopi < n
1 <= moviei, pricei <= 104
Each shop carries **at most one** copy of a movie moviei.
At most 105 calls **in total** will be made to search, rent, drop and report.

from sortedcontainers import SortedList

class MovieRentingSystem:
    def __init__(self, n: int, entries: list[list[int]]):
        self.available = {}
        self.rented = SortedList()
        self.shop_movie_price = {(shop, movie): price for shop, movie, price in entries}

        for shop, movie, price in entries:
            if movie not in self.available:
                self.available[movie] = SortedList()
            self.available[movie].add((price, shop))

    def search(self, movie: int) -> list[int]:
        return [shop for _, shop in self.available.get(movie, [])[:5]]

    def rent(self, shop: int, movie: int) -> None:
        price = self.shop_movie_price[(shop, movie)]
        self.available[movie].remove((price, shop))
        self.rented.add((price, shop, movie))

    def drop(self, shop: int, movie: int) -> None:
        price = self.shop_movie_price[(shop, movie)]
        self.rented.remove((price, shop, movie))
        self.available[movie].add((price, shop))

    def report(self) -> list[list[int]]:
        return [[shop, movie] for _, shop, movie in self.rented[:5]]