Post

1537 Maximum Score After Splitting A String

1537 Maximum Score After Splitting A String

Maximum Score After Splitting a String image

Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring).

The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring.

 

Example 1:

1
2
3
4
5
6
7
8
9
10
11
**Input:** s = "011101"
**Output:** 5 
**Explanation:** 
All possible ways of splitting s into two non-empty substrings are:
left = "0" and right = "11101", score = 1 + 4 = 5 
left = "01" and right = "1101", score = 1 + 3 = 4 
left = "011" and right = "101", score = 1 + 2 = 3 
left = "0111" and right = "01", score = 1 + 1 = 2 
left = "01110" and right = "1", score = 2 + 1 = 3

Example 2:

1
2
3
4
5
**Input:** s = "00111"
**Output:** 5
**Explanation:** When left = "00" and right = "111", we get the maximum score = 2 + 3 = 5

Example 3:

1
2
3
4
**Input:** s = "1111"
**Output:** 3

 

Constraints:

1
2
2 <= s.length <= 500
The string s consists of characters '0' and '1' only.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30

class Solution:
    def maxScore(self, s: str) -> int:
        res = 0
        left = []
        right = []
        temp0 = 0
        temp1 = 0
        for k in s:
            if k == "0":
                temp0 += 1
            left.append(temp0)
            if k == "1":
                temp1 += 1
            right.append(temp1)


        for idx, (k1, k2) in enumerate(zip(left, right)):
            if idx == len(right)-1:
                continue
            res = max(res, k1 + right[-1] - right[idx])
        return res



        



This post is licensed under CC BY 4.0 by the author.