118 Pascals Triangle
118 Pascals Triangle
Pascal’s Triangle 
Given an integer numRows, return the first numRows of Pascal’s triangle.
In Pascal’s triangle, each number is the sum of the two numbers directly above it as shown:
Example 1:
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**Input:** numRows = 5
**Output:** [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
Example 2:
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**Input:** numRows = 1
**Output:** [[1]]
Constraints:
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1 <= numRows <= 30
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impl Solution {
pub fn generate(num_rows: i32) -> Vec<Vec<i32>> {
let mut res : Vec<Vec<i32>> = Vec::new();
let mut temp : Vec<i32> = Vec::new();
temp.push(1);
res.push(temp.clone());
for i in 1..num_rows {
let mut f = 0;
let mut r = 1;
let mut temp_to_add = Vec::new();
temp_to_add.push(1);
while (r < temp.len()) {
temp_to_add.push(temp[f] + temp[r]);
f += 1;
r += 1;
}
temp_to_add.push(1);
res.push(temp_to_add.clone());
temp = temp_to_add;
}
res
}
}
This post is licensed under CC BY 4.0 by the author.
